Re^2: Splitting on escapable delimiter

Did you notice the bit highlighted below in the post where you got that regex from?

Intuatively, you want to use split '(?<=(?:##)+)\@', $s;; but that gets you:
[Variable length lookbehind not implemented in regex; ...

Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.

"Science is about questioning the status quo. Questioning authority".

In the absence of evidence, opinion is indistinguishable from prejudice.

Comment on Re^2: Splitting on escapable delimiter

Replies are listed 'Best First'.
Re^3: Splitting on escapable delimiter by wade (Pilgrim) on Mar 28, 2008 at 16:11 UTC
Doh! No, like an idiot, I looked at the problem and thought "I can solve that!". Thanks! -- Wade	[reply]