Just to expand on the above answers. In your example you pass arg1, $arg2, $arg3, $ar4, @data to the sub. What @_ gets is

$_[0] = $arg1, 
$_[1] = $arg2, 
$_[2] = $arg3, 
$_[3] = $arg4, 
$_[4] = $data[0], 
$_[5] = $data[1]
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So you can see by the above what is happening.

The ways to do this are as mentioned above, pass a reference to the array and dereference it, or assign all of the arguments to variables and then assign the rest of the @_ array to @info..

Update: per merlyn's comments below, have updated appropriately. Normally I would have written it like that, really not sure why I didn't in this case.