Re: Passing a variable to a sub process.

Inside sub mkdirs, you are declaring a new vaiable, $nossl, which is local to the sub. It is different from the variable of the same name which resides in the calling scope.

Perhaps what you want to do is:

#!/usr/bin/env perl
use warnings;
use strict;

my $nossl = 'foo';
mkdirs($nossl);
sub mkdirs {
    my $nossl = shift;
    print "nossl=$nossl\n";
}
[download]

This prints:

nossl=foo
[download]

Take a look at shift, perlsub and my.

Comment on Re: Passing a variable to a sub process. Select or Download Code

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Re^2: Passing a variable to a sub process. by misconfiguration (Sexton) on Apr 02, 2008 at 18:21 UTC
I hope to someday be as wise as you two, the depth of understanding you have is quite amazing. After the string $nossl was passed into the subroutine I changed some things. `my $nossl = shift; my $newsite = $nossl;` [download] Thanks again for your help, I learned a lot from this lesson.	[reply] [d/l]
Re^3: Passing a variable to a sub process. by Bilbo (Pilgrim) on Apr 02, 2008 at 18:58 UTC
Since you never use $nossl within your routine, this is equivalent to `my $newsite = shift;` [download] There is no significance in using the same name inside and outside the routine. This just says that you want to set $newsite using the first parameter passed to the subroutine.	[reply] [d/l]