in reply to last 10 ... next 10?
First set $start to one unless we're getting a param.
Then use two counters to track where to start and how many to process.unless(param('start')){ $start = 1 }
Then calculate the 'previous n' and 'next n' links.for(@array){ $c++; # count all items if($c >= $start){ # if $c count is = or greater than where to star +t $d++; # count items that match first test unless($d > $show){ # unless $d count is greater than how many + to show print # or whatever } } }
$previous = ($start-$show); unless($previous < 1){ # unless we're already at the beginning print qq~<a href="$url?start=$previous&show=$show"> Previous $show</a>~; } $next = ($start+$show); unless($next > $c){ # unless we're already at the end print qq~<a href="$url?start=$next&show=$show"> Next $show</a>~; }
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