Re: where is /\d+$/ result??

As this shows, $+ is the position of the match, not the value of the match. You need to use parentheses to indicate what you want to preserve, with $1 indicating the value of the first match. So your code should look like:

if ($frameDesc =~ /(\d+)$/ ) {
   print FH "FTP $1\n";
} else {
   print FH "FTP 0\n";
}
[download]

Or, if you were interested in Perl Golf, you might try

my $value = ($frameDesc =~ /(\d+)$/ ) ? $1 : 0;
print FH "FTP $value\n";
[download]

If you had two sets of parentheses in your regex and you wanted to manipulate the second value, you'd specify $2, etc.

Warning: the code is untested.

Comment on Re: where is /\d+$/ result?? Select or Download Code

Replies are listed 'Best First'.
Re^2: where is /\d+$/ result?? by ww (Archbishop) on May 04, 2008 at 03:17 UTC
See: Mastering Regular Expressions, 2nd ed., ISBN: 0-596-00289-0, Friedl, pp300-301. "$+ This is a copy of the highest numbered $1, $2, etc. explicitly set during the match." The "this" (perlvar) you cite phrases it this way: "$+ The text matched by the last bracket of the last successful search pattern. This is useful if you don't know which one of a set of alternative patterns matched." Whereas `perldoc perlretut` states this re `@+` and `@-`: In addition to what was matched, Perl 5.6.0 also provides the positions of what was matched with the "@-" and "@+" arrays.	[reply] [d/l] [select]
Re^2: where is /\d+$/ result?? by ikegami (Patriarch) on May 04, 2008 at 01:38 UTC
As [perlvar] shows, $+ is the position of the match, not the value of the match. You appear to be confusing `$+` with `@+`.	[reply] [d/l] [select]