Re^2: issues using bigrat

You changed
$s += $k / ($n-$k);
to
$s += ($n + 1 - $i) / $i;

The "+ 1" has the same effect as the "1 *" the OP used in his fixed version. Just like him, your $n and $i are plain integers, not big ints.

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Re^3: issues using bigrat by perl-diddler (Chaplain) on May 11, 2008 at 21:47 UTC
Yeah, you might think so, but if my code has the same problem, why does it not suffer the same problem calling numerator or denominator on "$s"? I mean the output is, I believe, what would expect if it was working correctly: `n = 1, s = 1, num=1, den=1 n = 2, s = 5/2, num=5, den=2 n = 3, s = 13/3, num=13, den=3 n = 4, s = 77/12, num=77, den=12 n = 5, s = 87/10, num=87, den=10 nums=1, 5, 13, 77, 87 dens=1, 2, 3, 12, 10` [download] Hmmm...not sure but it may that the original example that "worked" didn't really produce the right output or wasn't doing the right computation.	[reply] [d/l]
Re^4: issues using bigrat by ikegami (Patriarch) on May 11, 2008 at 22:15 UTC
why does it not suffer the same problem calling numerator or denominator on "$s"? "Same problem"? ~~His doesn't suffer from such a problem either. Both your results and his are BigRats~~ Update: Bad test. And you've already answered yourself.	[reply]