in reply to Re^3: Hash initialization works, but why?
in thread Hash initialization works, but why?

It gets more confusing (but then it gets more clear).

@foo is an array

Yes.

while (1,2,3) is a list

1, 2, 3 is a list. The parentheses have nothing to do with its listishness. The parentheses are there only so that the parser doesn't parse the whole expression as:

(@foo = 1), 2, 3;

... as it would if there were no grouping parentheses. They indicate which list you want to assign.

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Re^5: Hash initialization works, but why?
by throop (Chaplain) on Jun 05, 2008 at 14:14 UTC
    "Parentheses...have nothing...to do with...its listishness."

    Ah. Understanding is slowly dawning to this refugee from 10 years of LISP programming.

    throop