Re^2: regular expression issue

Hello, I am not getting what I want. I extracted the out put from the first part ie.

if (m/Reply issued by (.*?):(.*)/) {
  my $issuer = $1;
  my $msg = $2;
  print " $issuer \n $msg \n";
}
[download]

the $issuer is as below, you can see the \b interpreted as regex \b. ASlrssrajSRVPARTSP3930 is the Out put

Comment on Re^2: regular expression issue Download Code

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Re^3: regular expression issue by Anonymous Monk on Jun 06, 2008 at 10:03 UTC
In a double-quoted string, the sequence `"\b"` is a backspace control code. See following examples in double- and single-quoted strings. `perl -wMstrict -e "my $s = qq(abcdX\befg); print $s" abcdefg perl -wMstrict -e "my $s = qq(abcdX \befg); print $s" abcdXefg perl -wMstrict -e "my $s = q(abcdX\befg); print $s" abcdX\befg perl -wMstrict -e "my $s = q(abcdX \befg); print $s" abcdX \befg` [download] See Quote and Quote like Operators in perlop.	[reply] [d/l] [select]
Re^4: regular expression issue by sumesh.sasi (Initiate) on Jun 06, 2008 at 11:34 UTC
Thanks, Thats perfect. Good to know that difference.I was using the double quoted string, that causes the problem Thanks alot	[reply]