This is brilliant.... but what exactly is going on here? | [reply] |
Hello alphacoorg, and welcome to the Monastery!
$s=~/([^ :]+)/g
The square brackets create a bracketed character class and the initial ^ (caret) negates what follows, so this character class matches any character other than a space or a colon. The + quantifier means one or more, and the surrounding parentheses create a capture group. Finally,
the /g modifier creates a global match, and since the expression is evaluated in list context, the global match returns a list of matches.
That is, the regular expression returns a list of the substrings in ' ABC: 123 xyz: 100 def: YYY aaa: ZZZ' that do not contain space or colon characters:
("ABC", 123, "xyz", 100, "def", "YYY", "aaa", "ZZZ")
(You can verify this yourself by assigning the output of the regular expression to an array instead of a hash, and then printing out the array.)
In Perl, assigning a list to a hash populates the hash with key/value pairs taken in sequence from the list. So in this case, the hash is created with entries:
"ABC" => 123, "xyz" => 100, etc.
(Note that Perl’s “fat comma” =>, which is what you normally use when assigning key/value pairs to a hash, is really just an ordinary comma, functioning as a list separator, with the additional property that the expression on its left-hand side is turned into a string.)
Hope that helps,
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