print chomp <STDIN>

redkar has asked for the wisdom of the Perl Monks concerning the following question:

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Re: print chomp <STDIN> by marto (Cardinal) on Jul 24, 2008 at 08:29 UTC
Hi redkar, Did you read the documentation for chomp? chomp returns the number of characters removed. Also, you are missing a semicolon from the end of your second line. Try the following short example: `#!/usr/bin/perl use strict; use warnings; print "Please enter some text: "; my $input = <STDIN>; chomp($input); print "You typed $input\n";` [download] Read Basic Input and Output from the tutorials section of this site, and also the chomp documentation. Hope this helps Martin	[reply] [d/l]
Re^2: print chomp <STDIN> by parv (Parson) on Jul 24, 2008 at 08:48 UTC
While picking nit ... the semicolon would be optional on the second statement if it happens to the last statement.	[reply]
Re: print chomp <STDIN> by pjotrik (Friar) on Jul 24, 2008 at 08:36 UTC
You'll have to reverse your word order :-) `$_=<>; chomp; print;` [download]	[reply] [d/l]
Re^2: print chomp <STDIN> by redkar (Novice) on Jul 24, 2008 at 08:40 UTC
thanks for the help.... ll make sure that ill read the documentation properly before bothering the community	[reply]
Re: print chomp <STDIN> by broomduster (Priest) on Jul 24, 2008 at 08:34 UTC
You can only `chomp` an lvalue (this is the reason for the error that you get). Read `perldoc -f chomp` for an explanation. Even so, I suspect that `print chomp (my $value = <STDIN>);` [download] will not give you what you expect... Here it prints '1', not the chomped line from STDIN. Why, you ask? Because chomp returns the number of characters removed from the end of its argument(s). Again, see the documentation.	[reply] [d/l] [select]
Re: print chomp <STDIN> by Anonymous Monk on Jul 24, 2008 at 08:30 UTC
You're not using chomp() right. chomp($string) actually modifies $string itself, and its return value is not what you want to print -- it's 1 if chomp did something, 0 if not. see http://perldoc.perl.org/functions/chomp.html	[reply]
Re: print chomp <STDIN> by lorn (Monk) on Jul 24, 2008 at 16:08 UTC
I think that this error: error:Cant modify <HANDLE> in safe chop near <STDIN> its not a chomp error, the problem is that chomp try to modify <STDIN> and you cannot modify the <STDIN> :) like you cannot modify the special variable $1 when you get through of regexp. PS: sorry for my bad english :) Lorn -http://lornlab.org -slackwarezine.com.br	[reply]