Re^3: Reading a array

You're quite likely correct; it's just that from the code fragment given by the OP, I couldn't find where his array was being populated. I also tend to think that an event like $#arr1 giving an incorrect value is unlikely; I would expect that $#arr1 is among the Perl features least likely to have any bugginess. My thinking (I'm easily confused by symbolic references, so I'm likely wrong) is that $#arr1 isn't quite the same as scalar(@$arr1)-1.

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Comment on Re^3: Reading a array

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Re^4: Reading a array by jethro (Monsignor) on Aug 08, 2008 at 16:30 UTC
Exactly, if there is a @arr1 and you access it without any symbolic reference, then `$#arr1` is `scalar(@arr1)-1`. Only @arr1 is accessed here, the value of $arr1 is irrelevant and isn't used at all If we use $arr1 (totally different variable from @arr1) as a symbolic reference, then `@bingo=(1,2,3); $arr1='bingo'; print $#{$arr1}, scalar(@$arr1)-1, scalar(@bingo)-1;` [download] would print 222, as all three print expressions would be equivalent. In this case @arr1 is irrelevant and not used at all, only $arr1 as the symbolic reference and @bingo as the array	[reply] [d/l] [select]

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Re^4: Reading a array
by jethro (Monsignor) on Aug 08, 2008 at 16:30 UTC

Exactly, if there is a @arr1 and you access it without any symbolic reference, then $#arr1 is scalar(@arr1)-1. Only @arr1 is accessed here, the value of $arr1 is irrelevant and isn't used at all

If we use $arr1 (totally different variable from @arr1) as a symbolic reference, then

@bingo=(1,2,3);
$arr1='bingo';
print $#{$arr1}, scalar(@$arr1)-1, scalar(@bingo)-1;
[download]

would print 222, as all three print expressions would be equivalent. In this case @arr1 is irrelevant and not used at all, only $arr1 as the symbolic reference and @bingo as the array

[reply]
[d/l]
[select]