What happens if you try it without the leading percent sign? (The percent sign is a common prompt on a lot of UNIX systems. It's not really part of the command.)
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It returned the following:
5.812
The % perl _MLWP _le "print(LWP->VERSION)" script came from the Book by Sean M. Burke titled "Perl&LWP.
Thanks!
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You typed % ... at the command prompt?
If so, Vista is trying to run a program called "%", which is probably not what you want. Try it again without the percentage sign.
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Without the percent sign it returned: 5.812
The script "% perl -MLWP -le "print(LWP->VERSION)" came from the book by Sean M. Burke titled Perl & LWP.
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In most of my Perl books, the author will preface a command with a prompt like $, #, or %. When you're new to Perl, it can be confusing. What the author meant was perl -MLWP -le "print(LWP->VERSION)" On the other hand, when I run % perl -MLWP -le "print(LWP->VERSION)" bash will come back at me with "no such job". Obviously, we didn't want a job, but we wanted the version number of LWP.
Another way to find the version number is to use pmvers from pmtools.
Just run:
pmvers LWP
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[d/l]
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They also explain whats a prompt, like:
The dollar sign (and space) at the start of the line represents the shell prompt, which will probably look different on your system.
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