just pass yourself in an array of the actions

Trés cool idea++

Hi browserUK,

is there some problem in the below code :-

use strict;
use threads;
use threads::shared;
use Thread::Queue;

my @clientList =  qw(
    client1 client2 client3 client4 client5 client6
    );
my @queryList = qw(
    query1 query2 query3 query4 query5 query6
    );
my $maxnoofQueryThreads = 15;
my $maxnoofCompThreads = 30;
    
     my $globalQ = new Thread::Queue;
     my $queryBossID = threads->new(\&queryBoss,$globalQ);
     my $compBossID  = threads->new(\&compBoss,$globalQ,);
            
            $queryBossID->join;
            $compBossID->join;
            
sub queryBoss
 {
  my $q = new Thread::Queue;
                my $globalQ = shift;
                my @queryworkers = map {threads->new( \&queryworker, $
+q,$globalQ);} 1 .. $maxnoofQueryThreads;
                $q->enqueue(@queryList);
         $q->enqueue( ( undef ) x $maxnoofQueryThreads );
         $_->join for @queryworkers;
        }
sub compBoss
 {
  my $globalQ = shift;
  my @compworkers = map {threads->new( \&compworker, $globalQ);} 1 .. 
+$maxnoofCompThreads;
                #$q->enqueue(@queryList);
                $globalQ->enqueue( ( undef ) x $maxnoofCompThreads );
  $_->join for @compworkers;
 }
sub compworker
 {
  my $globalQ = shift;
  my $tid = threads->self->tid;
  while(my $workItem = $globalQ->dequeue)
   {
    print " the file is $workItem \n";
    #start comparison on the file and dump result in a new file and de
+l the file
   }
 }
sub queryworker
        {
              my( $Q ) = shift;
              my $globalQ = shift;
              my $tid = threads->self->tid;
              while( my $workItem = $Q->dequeue ) 
            {
    for( my $i = 0; $i < @clientList; $i++)
   {
                    #lock $mtxStdOut;
                    print " workitem  from thread $tid -->$workItem\n"
+; 
    ## Perform query
           ## worked on one client for query signal compBoss to start 
+doing comp
                                ## so enqueue the file location on dum
+p
    my $fileLoc = "$workItem"."$clientList[$i]";
    $globalQ->enqueue($fileLoc);
   }
            }
        }
[download]

is there some problem in the below code

Yes. You cannot have two different types of worker feeding off the same queue. How will each know whether what it pulled off the queue is for it or for the other type of worker?

You would at least need to use two queues, which isn't a problem and can be an effective way of decoupling two or more types of processing. But you still need to explain why you think this is a good idea? What are you hoping to gain from doing so?

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