Re: extract file name from a dynamic path

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Re^2: extract file name from a dynamic path by alexm (Chaplain) on Sep 07, 2008 at 01:41 UTC
While writing my last CUFP I found a warning about `basename` in File::Basename: This function is provided for compatibility with the Unix shell command `basename(1)`. It does NOT always return the file name portion of a path as you might expect. To be safe, if you want the file name portion of a path use `fileparse()`. I'd like to see an example of this, since I can't figure out what can be wrong with `basename`.	[reply] [d/l] [select]
Re^3: extract file name from a dynamic path by Anonymous Monk on Sep 07, 2008 at 06:12 UTC
Just keep reading, it says `C<basename()> returns the last level of a filepath even if the last level is clearly directory. In effect, it is acting like C<pop()> for paths. This differs from C<fileparse()>'s behaviour. # Both return "bar" basename("/foo/bar"); basename("/foo/bar/");` [download]	[reply] [d/l]
Re^4: extract file name from a dynamic path by alexm (Chaplain) on Sep 07, 2008 at 18:33 UTC
I was blind when I read that, thanks :)	[reply]