rqatar2003 has asked for the wisdom of the Perl Monks concerning the following question:
I'm really not sure how to do this at all, I need to be able to compare the input from a user to files in a directory. Basically I have files in /Users/johnsmith/data, how do I take the user input from my script and determine if it matches the file name in that directory.
Example:
File name in the /Users/johnsmith/data drectory is 1234.tar.Z My Script So far:
I know this is not correct and I can not figure out how to get this to work in Perl. Any help you could provide is greatly appreciated.#!/usr/bin/perl $fname = "empty"; while ($fname ne '/Users/johnsmith/data/$fname*'){ print "Please enter Filename: "; chomp($fname = <STDIN>); if ($fname ne '/Users/johnsmith/data/$fname*'){ print "File does not exist.\n\n"; print "Please enter Filename: "; } } print "I have found this $fname in your directory\n\n";
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Re: How to compare User Input to a file Name
by Corion (Patriarch) on Sep 23, 2008 at 06:26 UTC | |
by rqatar2003 (Initiate) on Sep 23, 2008 at 06:35 UTC | |
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Re: How to compare User Input to a file Name
by oko1 (Deacon) on Sep 23, 2008 at 16:24 UTC | |
by rqatar2003 (Initiate) on Sep 23, 2008 at 16:59 UTC | |
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Re: How to compare User Input to a file Name
by rqatar2003 (Initiate) on Sep 23, 2008 at 16:52 UTC | |
by toolic (Bishop) on Sep 24, 2008 at 00:46 UTC |