No, you are incorrect.

caller() doesn't return which 'function' calls you - it returns the package name, the file name and the line number of the caller; which is in the first three arguments. All the other arguments have to do how you are called. So, caller(0)[3] returns how you were called as.

If you want to find out which function called you (if there is such a function), you call caller(1), which gives you information how your caller is called.