Re^3: When doesn't the flip-flop operator work in all scalar contexts?

My take on it: The 'if' always follows a simple statement so the parser takes 'next,' as statement. Depending on context (in this case void?) this will be either a comma operator or a list with a dangling comma. It seems the comma operator also throws away dangling commas like a list:

> perl -e ' $d= (1,2); print "$d\n";'
2
> perl -e ' $d= (1,2,); print "$d\n";'
2
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