Re^2: How to start regexp from a X position

Thank!! great!!!, you open my mind, really i was knew that the solution is around that but i couldn't understand the documentation, perfect!!!!.

One last question, how works the modifier c and \G in a regexp

Could i do something like this:

my $x = "<0>";

for (qw {<1> <2> <3>}) {
    if ($x =~ /<\d+>/gc) {
        $x =~ s/\G(<\d+>)/$1$_/;
    }
}

say $x;
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Really thank JavaFan

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Re^3: How to start regexp from a X position by ikegami (Patriarch) on Oct 07, 2008 at 12:33 UTC
Thank!! great!!!, you open my mind, You picked the worst of the presented solutions solely because it used `pos` as you initially believed it should. That's the very definition of a closed mind.	[reply] [d/l]
Re^4: How to start regexp from a X position by pkt (Initiate) on Oct 07, 2008 at 12:57 UTC
Don't angry with me!!!, yes you right i'm a little closed mind, and you and JavaFan help me open it, when you said use .* i said me couldn't be more stupid it's right!!!, i really fight before posting here for many hours and i cuoldn't find a solution, becouse of that i reasearch about not common at least for me functio, variable and operators like pos, $&, \G, etc, etc, but finally you right :-) Thank to both	[reply]
Re^3: How to start regexp from a X position by JavaFan (Canon) on Oct 07, 2008 at 12:44 UTC
I've no idea how to incorporate the /c modifier. It'll be pointless for two reasons. First, one sets pos() before matching, so who cares about the effect of /c. Second, /c would only kick in if you add a substring `foo` to $x, and the next time around, `foo` isn't there.	[reply]
Re^4: How to start regexp from a X position by pkt (Initiate) on Oct 07, 2008 at 13:01 UTC
Ok, JavaFan	[reply]