Hi I have a problem with my script. When I run it like this: FieldCompare.pl -t sur out20111_23866.sorted SUR_P1023866.sorted -o results it EXITS with the following statement: **** Specify name of the output file! ***** But I passed in -o parameter called "results" SO WHY DOES $opt_o" variable NOT contain "results" (or any other parameter I pass to that option) string ? Thanks!

#!/usr/bin/perl -w

use strict;
use Getopt::Long;
use Getopt::Std;

#ArrayS of hashes
my @MainFields = ();
my @ReservedINFO = ();
my $output_type;
my $outputFile;

our($opt_h, $opt_c, $opt_t, $opt_o);
getopts('hc:t:o:');

# Reading specified options and calling particular initialization func
+tions
sub Init {

  my $file1;
  my $file2;
  my $tmp;
  
  if(defined($opt_h)){
    print Syntax();
    exit;
  }

  if(!defined($opt_t)){
    print "\n***** Specify the type of the output! *****\n";
    print Syntax();
    exit;
  }
  
  $output_type = $opt_t;
  $file1 = $ARGV[0];
  $file2 = $ARGV[1];
  
  if((!defined($file1)) || (!defined($file2))){
    print "\n***** Specify the INPUT files! *****\n";
    print Syntax();
    exit;
  }
  
  print "\nFirst file - $file1\nSecond File - $file2\n";
  
  if(!defined($opt_c)){
    print "\nNo config file provided, defualt configuration will be us
+ed!\n";
    init_default_config($output_type);
  } else {
    read_config_file($output_type);
  }
  
  if(!defined($opt_o)){
    print "\n***** Specify name of the output file! *****\n";
    print Syntax();
    exit;
  }
  
  $outputFile = $opt_o;
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I mean if THE VERY SAME CODE WORKS FOR 'T' OPTION why DOES IT NOT WORK for 'O' option ?