Re:{3} Constructing 32-bit hexadecimal integers

Nah, use unpack at will.

You will have to pad them missing values:

$a = "\001"; #just another hex string
$a = ("\000" x (4-length($a))).$a; #Zero pad that string
print unpack 'L', $a; #Hey, that's one!
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Jeroen
"We are not alone"(FZ)

Comment on Re:{3} Constructing 32-bit hexadecimal integers Download Code

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(tye)Re: Constructing 32-bit hexadecimal integers by tye (Sage) on Apr 12, 2001 at 00:54 UTC
Well, it is either 1 or 0x01000000, depending on your platform. Use 'N' or 'V' in place of 'L' if you want to use big- or little-endian format (respectively) regardless of your current platform. - tye (but my friends call me "Tye")	[reply]