What would be the approach if the string were an octet string? I came across more genius documentation for a different OID:
A string of octets containing one bit per VLAN in the
management domain on this trunk port. The first octet
corresponds to VLANs with VlanIndex values of 0 through 7;
the second octet to VLANs 8 through 15; etc. The most
significant bit of each octet corresponds to the lowest
value VlanIndex in that octet. If the bit corresponding to
a VLAN is set to '1', then the local system is enabled for
sending and receiving frames on that VLAN; if the bit is set
to '0', then the system is disabled from sending and
receiving frames on that VLAN.
GrandFather has a great example in a post, Re: Convert SNMP Octet String to Array, to convert the octet string, but I don't think I understand how the ranges were created from the bit number. Using GrandFather's example I can convert the string properly, but I can't figure out how to show the VLANs in the range format (1-10,15,20-30, etc).
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A string of octets containing one bit per VLAN in the management domain on this trunk port. The first octet corresponds to VLANs with VlanIndex values of 0 through 7; the second octet to VLANs 8 through 15; etc. The most significant bit of each octet corresponds to the lowest value VlanIndex in that octet.
Well that's pretty clear. It's also the exact reverse of the previous form.
Perl's bit-vector is similar, except that the bits are in the opposite order in each byte. So you can translate between this format and a Perl bit-vector so:
sub xlat {
my ($octets) = @_ ;
return pack('B*', unpack('b*', $octets)) ;
} ;
The translation reverses itself, and as you can see unpacks the bytes in one bit order and promptly repacks in the other. This shows the effect:
my $test = "\xC5\x11\x01\x80\x5A" ;
print showbits($test), "\n" ;
print showbits(xlat($test)), "\n" ;
print showbits(xlat(xlat($test))), "\n" ;
sub showbits {
my ($octets) = @_ ;
my $s = unpack('B*', $octets) ;
$s =~ s/([01]{8})(?=[01])/$1:/g ;
return $s ;
} ;
giving:
11000101:00010001:00000001:10000000:01011010
10100011:10001000:10000000:00000001:01011010
11000101:00010001:00000001:10000000:01011010
which appears to be what's required. | [reply] [d/l] [select] |
Thanks again. I don't think I'm fully grasping how vec works, even after reading the doc, or the routine using vec to map the bits to the vlans and creating the ranges.
The routine formating numbers like 1,2,3 as 1-3 is great, but doesn't seem to work properly with the octet string example. Of course it won't work with Grandfather's example from what I can see since @ports just contains the VLANs allowed
Trying to shoehorn the previous example into this one:
sub xlat {
my ($octets) = @_ ;
return pack('B*', unpack('b*', $octets)) ;
} ;
my $test = '0x4000040000000200800000000000000000000002'
.'0000000000c004000108008000000000000000000'
.'00000000000000000000000000000000000000000'
.'00000000000000000000000000000000000000000'
.'00000000000000000000000000000000000000000'
.'00000000000000000000000000000000000000000'
.'00000000000';
my $bits;
$bits = showbits($test);
my @s = ranges($bits);
print "Ranges: ", join(', ', @s);
$bits = showbits(xlat($test));
@s = ranges($bits);
print join(',',@s);
$bits = showbits(xlat(xlat($test)));
@s = ranges($bits);
print join(',',@s);
sub ranges{
my $test = shift;
my $r = undef ;
my @s = () ;
for my $vn (1..length($test) * 8) {
if (vec($test, $vn, 1)) {
if (!defined($r)) { push @s, "$vn-" ; } ;
$r = $vn ;
}
else {
if (defined($r)) { $s[-1] .= "$r" ; $r = undef ; } ;
} ;
} ;
return @s;
}
sub showbits {
my ($octets) = @_ ;
my $s = unpack('B*', $octets) ;
$s =~ s/([01]{8})(?=[01])/$1/g ;
ranges($s) ;
} ;
Should, at least in my misunderstanding, produce Ranges: 1,21,54,64,158,200-201,213,231,236,248.
Instead it produces:
Ranges: 1-1, 4-5, 8-8, 10-10, 12-13, 18-18, 20-21, 24-24, 28-291-1,4-5,8-8,10-10,12-13,18-18,20-21,28-291-1,4-5,8-8,10-10,12-13,18-18,20-21,24-24,28-29
Using GrandFather's example
my $ports = '0x4000040000000200800000000000000000000002'
.'0000000000c004000108008000000000000000000'
.'00000000000000000000000000000000000000000'
.'00000000000000000000000000000000000000000'
.'00000000000000000000000000000000000000000'
.'00000000000000000000000000000000000000000'
.'00000000000';
my $basePort = 0;
my @ports;
$ports = substr $ports, 2;
while ($ports) {
my $octet = hex substr $ports, 0, 2, '';
my $index = 0;
while ($octet) {
next unless $octet & 0x80;
push @ports, $basePort + $index;
} continue {
++$index;
$octet = ($octet << 1) & 0xff;
}
$basePort += 8;
}
print join ',', @ports;
produces: 1,21,54,64,158,200,201,213,231,236,248
After hours of playing with both these examples I managed to confuse myself even more. Can you point out what I'm missing?
Update:After some more tinkering I came up with the following kludge to format Grandfather's example, but something tells me there's a better way to do this. Still haven't figured out how to convert the string properly with vec.
my $ports = '0x4000040000000200800000000000000000000002'
.'0000000000c004000108008000000000000000000'
.'00000000000000000000000000000000000000000'
.'00000000000000000000000000000000000000000'
.'00000000000000000000000000000000000000000'
.'00000000000000000000000000000000000000000'
.'00000000000';
my $basePort = 0;
my @ports;
$ports = substr $ports, 2;
while ($ports) {
my $octet = hex substr $ports, 0, 2, '';
my $index = 0;
while ($octet) {
next unless $octet & 0x80;
push @ports, $basePort + $index;
} continue {
++$index;
$octet = ($octet << 1) & 0xff;
}
$basePort += 8;
}
print join ',', @ports,"\n";
range_format(@ports);
sub range_format{
my (@numbers,$i,$start,$end);
@numbers = @_;
for ($i = 0; $i < @numbers; ++$i){
my $prev = $numbers[$i-1];
my $next = $numbers[$i+1];
my $cur = $numbers[$i];
if (($cur+1 == $next) and ($cur-1!= $prev)){
$start = $cur;
}
if (($cur-1 == $prev) and ($cur+1 != $next)){
$end = $cur;
}
if ((defined $start) and (defined $end)){
print "$start-$end,";
$start = undef;
$end = undef;
}else{
unless((defined $start)||(defined $end)){print "$cur,";}}
}
}
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