Re^2: Problems with Variable Scope in Perl

Thank you very much Graff! Yes, saving the @SCOPclass array is intentional. One more question though: could you kindly explain:

$pdbString[$#pdbString] .= $_;
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What do the $ followed by # represent? As I am still new at Perl I get confused between these symbols! Thanks for all your help :)

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Re^3: Problems with Variable Scope in Perl by ruzam (Curate) on Nov 03, 2008 at 02:34 UTC
The string contained in $_ is being joined to the string in the last element of @pdbString This code could also be written as: `$pdbString[@pdbString - 1] .= $_;` [download] or `$pdbString[-1] .= $_;` [download] Which I find simpler to read (negative index references the array starting from the end).	[reply] [d/l] [select]
Re^3: Problems with Variable Scope in Perl by ig (Vicar) on Nov 03, 2008 at 02:16 UTC
$#pdbString is the index of the last element in array @pdbString. There are more examples and explanations in perldata.	[reply]
Re^3: Problems with Variable Scope in Perl by graff (Chancellor) on Nov 03, 2008 at 03:20 UTC
Yes, saving the @SCOPclass array is intentional. ... and so the fact that you never use the saved values would seem to be unintentional?	[reply]
Re^4: Problems with Variable Scope in Perl by Anonymous Monk on Nov 05, 2008 at 15:53 UTC
I have saved the @SCOPclass array but I am still figuring out what I want to do with it in the scope of my work! So yes, saving the values is intentional, but where I want to output the variable and how I want to use the saved values remains unintentional :)	[reply]