You're so close to getting this. The main problems with your code are my $one_number = $numbers[${$href{$name}} - 1]; and print "$name\t\t${$href{$name}}\t$one_number\n"; You're having some trouble with derefencing the arrays (and also with choosing the "one number"). The correct syntax would be $numbers[$href{$name}->[0]] (assuming you want the first element), or $numbers[${$href{$name}}[0]].

After seeing your updates, I think I'm a bit confused about exactly what you're trying to accomplish now. I had initially thought that you wanted to match each value in the array against every line in File2. If that is still the case, you need to add a nested loop.

Anyway, here is some updated code. I hope this does what you need it to do.

#!/usr/bin/perl -w

use strict;
use warnings;

my %href;

open my $fh, "<", "File1.txt" or die "Cannot open File1: $!";

while (<$fh>) {
    chomp;
    push @{$href{$1}}, $2 if /(\S+)\s+(\S+)/;
}

while (my ($key, $value) = each(%href)) {
    print "$key, (@{$value})\n";
}

close $fh;

open $fh, "<", "File2.txt" or die "Cannot open File2: $!";

{
    local $/ = '>';

    while ( <$fh> ) {
        chomp;
        next unless ( s{ \A (\S+) \s+ (?= \d ) }{}xms and exists( $hre
+f{$1} ));

        my $name = $1;
        my @numbers = split /\D+/;

        for my $index (@{$href{$name}}) {
            next if $index > $#numbers;
            if ($numbers[$index] >= 20) {
                print "$name\t\t$index\t$numbers[$index]\n";
            }
        }
    }
}
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