I don't see anything wrong with your regex. I tried

print "$1\n$2\n" if $var =~ /^\((.*)\),(.*)$/;
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on your string and got

this is a good idea!
 No it's not
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exactly as I would expect.

On a slightly different topic, I would have generally used ([^)]*) rather than (.*) as the first capture. It is more likely to do what you want.