in reply to sub fuction inside sub functioin?
sub outer { my ($param) = @_; local *inner1 = sub { ... }; local *inner2 = sub { ... }; ... inner2(inner1($param)); }
|
|---|
| Replies are listed 'Best First'. | |
|---|---|
|
Re^2: sub fuction inside sub functioin?
by LanX (Saint) on Dec 07, 2008 at 20:23 UTC | |
by ikegami (Patriarch) on Dec 07, 2008 at 20:39 UTC | |
by LanX (Saint) on Dec 07, 2008 at 21:18 UTC | |
by ikegami (Patriarch) on Dec 07, 2008 at 23:20 UTC | |
by LanX (Saint) on Dec 08, 2008 at 02:05 UTC | |
| |
by gone2015 (Deacon) on Dec 08, 2008 at 02:08 UTC |