Re^2: How can POE use a hash reference like a hash?

... not in all cases - Re^2: Multidimensional array.

A user level that continues to overstate my experience :-))

Comment on Re^2: How can POE use a hash reference like a hash?

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Re^3: How can POE use a hash reference like a hash? by rcaputo (Chaplain) on Dec 27, 2008 at 15:48 UTC
That node seems to agree with me: Arrows are optional between two subscripts. In `$x->[0]->[1]`, `$x` is not a subscript but both `[0]` and `[1]` are. We may remove the second arrow without changing the expression, giving `$x->[0][1]`. The arrow between `$x` and `[0]` isn't between two subscripts, however, so it is required to maintain equivalence with the original expression. `-- Rocco Caputo - http://poe.perl.org/`	[reply] [d/l] [select]

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Re^3: How can POE use a hash reference like a hash?
by rcaputo (Chaplain) on Dec 27, 2008 at 15:48 UTC

That node seems to agree with me: Arrows are optional between two subscripts.

In $x->[0]->[1], $x is not a subscript but both [0] and [1] are. We may remove the second arrow without changing the expression, giving $x->[0][1]. The arrow between $x and [0] isn't between two subscripts, however, so it is required to maintain equivalence with the original expression.

-- Rocco Caputo - http://poe.perl.org/

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