in reply to Re^4: Why is this code so much slower than the same algorithm in C? (2s)
in thread Why is this code so much slower than the same algorithm in C?
Performance is essentially the same if you write 46558512 as (9*7*11*13*16*17*19).perl -le 'my $i = 0;do { $i += 20 } while( $i%46558512 ); print $i' 232792560
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Re^6: Why is this code so much slower than the same algorithm in C? (why)
by tye (Sage) on Dec 16, 2008 at 02:55 UTC | |
by tilly (Archbishop) on Dec 16, 2008 at 17:42 UTC |