in reply to Re^4: How to call a sub reff from a hash
in thread How to call a sub ref from a hash

Then you want to re-read perldata and perlreftut because $foo->{'bar'} has nothing to do with trying to get at $foo{'bar'}.

The cake is a lie.
The cake is a lie.
The cake is a lie.

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Re^6: How to call a sub reff from a hash
by NateTut (Deacon) on Dec 15, 2008 at 22:19 UTC
    Originally I had: &$Procedures{$Procedure}($Parameter); but that gives me the same error.