Re^8: How to call a sub reff from a hash

I apologize you are right of course, I must have copied wrong before. The real problem here is that I'm not understanding the syntax. Thanks for all the help.

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Re^9: How to call a sub reff from a hash
by ikegami (Patriarch) on Dec 16, 2008 at 04:52 UTC

I'm not understanding the syntax

This Can be written more clearly as

${$aref}[$i] $aref->[$i]

${$href}{$k} $href->{$k}

&{$cref}($arg) $cref->($arg)

In this case, the code ref is stored in a hash, so $cref is a hash lookup.

my $cref = $hash{$k}; $cref->($arg)

    |
    v

( $hash{$k} )->($arg);

    |
    v

$hash{$k}->($arg);
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Re^10: How to call a sub reff from a hash

by NateTut (Deacon) on Dec 16, 2008 at 19:12 UTC

Thank you that helped clear up my misunderstanding.

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