Re^2: Understanding -> function

Thanks Monks.. The formatting code will be below where there will be $1, $2 and $3 values.


( /^BAK(\w+)\s+(\d+)\s+([\w\_]+)\s*/i )
[download]

But I still do not understand the use of =$1; and $3; at end of code for below two lines.

        $bakjobs->{"$2"}{"dbt"} = $1;
        $bakjobs->{"$2"}{"cdt"} =$3;
[download]

Please explain.. Appreciate your help..

Comment on Re^2: Understanding -> function Select or Download Code

Replies are listed 'Best First'.
Re^3: Understanding -> function by plobsing (Friar) on Dec 28, 2008 at 20:31 UTC
That's an assignment. It puts the value of `$1` into `$backjobs->{$2}{dbt}`. Likewise, it puts the value of `$3` into `$bakjobs->{$2}{cdt}`. Also note that `\w` matches underscores, so the character class in the regex is redundant. See perlretut.	[reply] [d/l] [select]
Re^3: Understanding -> function by AnomalousMonk (Archbishop) on Dec 29, 2008 at 00:33 UTC
$1, $2, $3 and so on are capture variables. Specifically, in the regex `/^BAK``(\w+)``\s+``(\d+)``\s+``([\w\_]+)``\s/i` the sub-expressions `(\w+)`, `(\d+)` and `([\w\_]+)` (which, as already noted, is the same as `(\w+)` since `\w` is `[a-zA-Z0-9_]`, but under the control of locale) are capturing groups*, and whatever these groups match, if anything, is available through the capture variables. See perlre, perlretut (especially Extracting matches) and perlrequick for further discussion of capturing groups and capture variables; in particular, how the number of the variable ($1, $2, $3, etc.) relates to the order of the capture group in the regex.	[reply] [d/l] [select]