Re: variable sees it, array doesn't

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Re^2: variable sees it, array doesn't - stumped! by gone2015 (Deacon) on Dec 31, 2008 at 18:15 UTC
`print (join ' ', @array), "\n";` ...sadly, Perl's syntax will have you for breakfast here... the brackets will be interpreted as delimiting the parameters of the print "function" -- see perlfunc.	[reply] [d/l]
Re^3: variable sees it, array doesn't - stumped! by DStaal (Chaplain) on Dec 31, 2008 at 18:56 UTC
You are right: I thought I was using it someplace, but everywhere I've got it I put something else in before the output of the join. Either `print((join ' ', @array), "\n");` or `print (join(' ', @array)), "\n";` or even `print join(' ', @array), "\n";` should work better.	[reply] [d/l] [select]
Re^4: variable sees it, array doesn't - stumped! by JadeNB (Chaplain) on Jan 01, 2009 at 18:44 UTC
`print (join(' ', @array)), "\n"` Unfortunately, this one still doesn't work, for the same reason that `print (join ' ', @array), "\n"` doesn't. An option that I frequently use, though it feels dirty, is `print '', (EXPR), "\n"`.	[reply] [d/l] [select]
Re^2: variable sees it, array doesn't - stumped! by shrdlu (Novice) on Dec 31, 2008 at 17:06 UTC
It's true what they say then, there's always another way! Thanks for this, it does indeed look a little more intuitive.	[reply]