Re: ||= in Hash Slice

I'm not aware of a convenient per-item combination. I hear that Perl 6 will have "hyper-operators" for that, when it reaches a stable release version >= 1.0.

I'd do that with a map, as I always use map when transforming one list into another:

@{$audit}{@$copy_fields} = map { defined $item->{$_} ? $item->{$_} : '
+' } @$copy_fields;
[download]

Your code will happily replace a value of "0" by "", and I guess that's not intended.

Comment on Re: \|\|= in Hash Slice Download Code

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Re^2: \|\|= in Hash Slice by Brovnik (Hermit) on Jan 06, 2009 at 12:15 UTC
Yup, I guess that works, but I was hoping for something a bit more elegant. `@{$audit}{@$copy_fields} = map { $item->{$_} \|\| '' } @$copy_fields;` [download] Is probably the nearest I'll get. P.S. The '' vs. 0 difference is irrelevant here in my case, I just want avoid undefs. -- Brovnik	[reply] [d/l]
Re^3: \|\|= in Hash Slice by Bloodnok (Vicar) on Jan 06, 2009 at 17:56 UTC
That may not, probably won't, work in all cases ... consider when the value of `$item->{$_}` is `0`: in this case, the wanted value of `0` will be overwritten by the empty string, since `$item->{$_}` is, from a perl POV, false. Hence Corions suggestion, tho' not quite what you were seeking, is better. A user level that continues to overstate my experience :-))	[reply] [d/l] [select]