Re^2: How to replace greedy alternation?

This code does not work:

/^(?=.*a)(?=.*b)(?=.*c).*d/
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For example, when used in the code below nothing s returned.

echo bacd| perl -ne '/^(?=.*a)(?=.*b)(?=.*c).*d/; print "$1 $2 $3\n";'
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Comment on Re^2: How to replace greedy alternation? Select or Download Code

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Re^3: How to replace greedy alternation? by jwkrahn (Abbot) on Jan 28, 2009 at 07:25 UTC
That is because there are no capturing parentheses in your regular expression and so `$1`, `$2` and `$3` are not affected and thus contain nothing.	[reply] [d/l] [select]