Re: Check if value exists into an array in a hash

If I understand what you're doing, I think, yes, it will do what you want.

exists($list[$num])
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Will tell if there is an item of some kind, possibly undefined, at index $num in list $list.

I think $#{$arrayref} is what you're looking for with the 2nd question. EG $#{$hash_of_lists{$foo}}.

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Re^2: Check if value exists into an array in a hash by kennethk (Abbot) on Feb 10, 2009 at 20:09 UTC
The issue is that `push @list, $num` doesn't set element `$list[$num]`, so the tests don't correlate. If instead the OP used `$list[$num] = 1;` or equivalent, then [she\|he] would get a false positive with exists if [she\|he] set `$list[5]` and then checked `$list[3]` - defined would give correct results, though.	[reply] [d/l] [select]
Re^3: Check if value exists into an array in a hash by pileofrogs (Priest) on Feb 10, 2009 at 21:53 UTC
Oy, yes. I see what you mean. The array will grow to accomodate it's highest index, and therefore all lower indexes will come into existence. I think the OP should use a hash. Clearly, it's a hash-ish behavior he/she wants. The fact that the keys are numbers is making it look like a list problem, but really, it's a hash problem.	[reply]