Hi balakrishnan, To the best of my knowledge you can't use a substitution. however you could use split to achieve this.

#!/usr/bin/perl
use strict;
my $i;
my @values;
my $string ="age 42 name Utilitarian FamilyName";
($i,@values)= split(/age|name/, $string);
for ($i=0;$i<@values;$i++){
   print "$i, $values[$i]\n";
}
[download]

This is ugly, but does what you want in one step (ie.applies the regex and makes the matches available in an array.