Re^3: Why does 'print shift sort @array' not work?

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Re^4: Why does 'print shift sort @array' not work? by ikegami (Patriarch) on Feb 26, 2009 at 20:32 UTC
We both known Perl is very finicky when parens are omitted. But `print [sort @array]->[0]` [download] would still be simpler, no?	[reply] [d/l]
Re^5: Why does 'print shift sort @array' not work? by Fletch (Bishop) on Feb 26, 2009 at 20:40 UTC
But that's a whole character longer . . . :) (But then again the square version requires hitting shift one less time so it has that going for it :) `print +(sort @array)[0]; print [sort @array]->[0];` [download] Possibly could an interesting benchmark if anyone's so inclined: does slicing the value off the stack beat constructing the anonymous arrayref (which gets tossed immediately) then deref'ing, and what the falloff is as `@array` grows. The cake is a lie. The cake is a lie. The cake is a lie.	[reply] [d/l] [select]
Re^5: Why does 'print shift sort @array' not work? by hbm (Hermit) on Feb 26, 2009 at 21:07 UTC
Aren't the following functionally equivalent, i.e. Sort, make an array and a reference to it, dereference it, get the [first] item? `print [sort @array]->[0]; print @{[sort @array]}[0];` [download]	[reply] [d/l]
Re^6: Why does 'print shift sort @array' not work? by JavaFan (Canon) on Feb 26, 2009 at 21:36 UTC
Aren't the following functionally equivalent, Technically, no. `[sort @array]->[0];` does return a single element. `@{[sort @array]}[0];` however is a slice with one element. I would have expected it to warn - just as @array[0] will warn. The PC way to write it is: `print ${[sort @array]}[0];` [download]	[reply] [d/l] [select]
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