in reply to Better way to do this, regex etc.

Here is another way to do it:

#!/usr/bin/perl use warnings; use strict; my $bug_fix_msg = "this 33,44 is a fix for mybug44,99 real \ bug 99 again bug33r bug1722,3 bUg:99, \ bugs:456, 17, 24 bugs 42,58 bug: 50,50"; my %unique; while ( $bug_fix_msg =~ /\bbugs?:?([\s\d,]*)\b/ig ) { print "$1\n"; $unique{ $_ }++ for $1 =~ /\d+/g; } my @sorted = sort { $a <=> $b } keys %unique; print "unique: @{[keys %unique]}\n"; print "sorted: @sorted\n";

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Re^2: Better way to do this, regex etc.
by mintz (Initiate) on Mar 04, 2009 at 10:48 UTC
    Hey thanks to everyone for your help. I decided to use jwkrahn's method, but I also realised that my regex wouldn't reject "bug,,8 bug,9". So I've added a lookahead to the regex filter. As follows:
    #!/usr/bin/perl use warnings; use strict; my $bug_fix_msg = "this 33,44 is a fix for mybug44,99 real \ bug 99 again bug33r bug1722,3 bUg:99, \ bugs:456, 17, 24 bugs 42,58 bug: 50,50 \ buggy99 bug3,:8,34 bug,,49 bug,84 bug:s12"; print "test string: $bug_fix_msg\n\nFiltered:\n"; my %unique; while ( $bug_fix_msg =~ /\bbugs?:?(?!,)([\s\d,]*)\b/ig ) { print "$1\n"; $unique{ $_ }++ for $1 =~ /\d+/g; } print ("End Filtered\n\n"); my @sorted = sort { $a <=> $b } keys %unique; print " unique: @{[keys %unique]}\n"; print " sorted: @sorted\n";
    Output as follows:
    test string: this 33,44 is a fix for mybug44,99 real bug 99 again bug33r bug1722,3 bUg:99, bugs:456, 17, 24 bugs 42,58 bug: 50,50 buggy99 bug3,:8,34 bug,,49 bug,84 bug:s12 Filtered: 99 1722,3 99, 456, 17, 24 42,58 50,50 3 End Filtered unique: 50 3 58 17 456 42 99 24 1722 sorted: 3 17 24 42 50 58 99 456 1722
    Thanks again for the help. I've always thought of regex parsing as a bit of a black art, but I'm starting to get the hang of it.