in reply to Working with Variables

Yes, it is. Do something like this: 

$var=<<BLAH;

if($lbha = 'poo'){
   print "oh";
}

BLAH

eval $var;

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You're probably wondering about that little eval $var part. Well, all eval does is evaluate the code and execute it as a separate script. Otherwise you would just literally print "if($lbha = 'poo'){ do stuff.... }" out of the screen, which isn't what you want.

I hope I understood your question and answered it properly.

Tiptoeing up to a Perl hacker.
Dave AKA damian

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Re: Re: Working with Variables
by Anonymous Monk on Apr 24, 2001 at 00:16 UTC 
    Lets say that inside a
$var=<<VAR;
print "Blah";
VAR

print<<BLAH;
print "Blah";
eval $var;
BLAH

will that replace eval $var with "Blah"?

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      No, it will replace $var with the string print "Blah";\n, so when you run it you'll get 

      print "Blah";
eval print "Blah";
;

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      as your output, which is probably not what you want.

      See Masem's post and stephen's post below for how to do more interesting interpolation.


      If God had meant us to fly, he would *never* have give us the railroads.
          --Michael Flanders

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      No, what you want is 

      $var=<<BLAH;

print "Blah";

BLAH

eval $var;

      [download]


      Because when it executes it it will print Blah out on the screen because you have print "Blah"; already inside $var;

      UPDATE:WOULD SOMEONE MIND TELLING ME WHAT IS SO WRONG ABOUT THIS POST THAT I GOT A -- ON IT?? THIS IS SO *beeping* REDICULOUS. CONSTANTLY BEING ATTACKED.

      Tiptoeing up to a Perl hacker.
      Dave AKA damian
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