Re^2: backreference replaced as literal or just fails

Sorry for missing the input part. With respect to your binding point, I must not understand the usage. I understand

$rrow_test =~ s/$rex[0]/$rex[1]/ig;
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to mean

"Replace the first occurrence of $rex[0] with $rex[1]."
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I'm setting the $rex array values on the 'split' line of the code. Am I understanding your point/question correctly or have I missed the mark altogether? Thanks.

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Re^3: backreference replaced as literal or just fails by kennethk (Abbot) on Mar 10, 2009 at 19:43 UTC
The "binding" issue is that you didn't give us any possible values for $rrow_test, thus making it harder to determine intent. In any case, the issue you are likely encountering is that you expect your strings to get interpolated twice. According to Regexp Quote-Like Operators, variables you pass get interpolated at run time. This means that "$rex[1]" gets interpolated to "$1", the literal value (Update: as GrandFather points out below). Your solution is to doubly interpolate the string, using the ee modifier. Note this is potentially a serious security risk. Also note your i modifier is useless in your current construct, as you already handle both upper- and lower-case letter.	[reply]
Re^3: backreference replaced as literal or just fails by zwon (Abbot) on Mar 10, 2009 at 19:45 UTC
"Replace the first occurrence of $rex[0] with $rex1." Actually `/g` means replace all occurrences.	[reply] [d/l]