Integer overflow in hexadecimal number

bh_perl has asked for the wisdom of the Perl Monks concerning the following question:

I got an error said " Integer overflow in hexadecimal number at /acec/nv2am/bin/nokscan line 294.".

The error message happened once i convert hex to int from hextoint function. The function as below. Could somebody help me how to solve to error ?

sub hextoint {
        my $hex = shift;

        return sprintf ("%20d", hex($hex));
}
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Comment on Integer overflow in hexadecimal number Download Code

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Re: Integeer overflow in hexadecimal number by ikegami (Patriarch) on Mar 11, 2009 at 06:02 UTC
`hex` can only handle numbers as big as the integers your Perl can handle. On a Perl with 32-bit integers, `>perl -le"hex('0xFFFFFFFF')" >perl -le"hex('0x100000000')" Integer overflow in hexadecimal number at -e line 1.` [download] Math::BigInt's `from_hex` could be of use. There could be other solutions as well if we were familiar with the bigger picture.	[reply] [d/l] [select]
Re: Integer overflow in hexadecimal number by AnomalousMonk (Archbishop) on Mar 11, 2009 at 07:56 UTC
bh_perl: Also note that had you been using warnings, your warning message would have been more enlightening. `>perl -w -Mstrict -le "my $n = hex '0x100000000'; print $n; " Integer overflow in hexadecimal number at -e line 1. Hexadecimal number > 0xffffffff non-portable at -e line 1. 4294967296` [download]	[reply] [d/l]