in reply to Re: Re: Why not support this syntax?
in thread Why not support this syntax?
And so forth.A < B >= C -> (A < B) && (B >= C) A > B < C -> (A > B) && (B < C)
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Re: Re^3: Why not support this syntax?
by clemburg (Curate) on Apr 24, 2001 at 19:29 UTC | |
by MeowChow (Vicar) on Apr 24, 2001 at 20:12 UTC | |
by scott (Chaplain) on Apr 30, 2001 at 18:13 UTC |