in reply to Re^2: partition of an array
in thread partition of an array
Does not.
Output:
$VAR1 = [ '1', '1', '2', '2' ]; $VAR2 = [ '1', '2', '2', '4' ]; we have 6 and 9
You dropped the sort bit!
... some time passes ...
Just snagging the biggest one and stuffing it in a sack works pretty well for the knapsack problem... and since this one was only 2 partitions it didn't do too bad ;)
@_=qw; ask f00li5h to appear and remain for a moment of pretend better than a lifetime;;s;;@_[map hex,split'',B204316D8C2A4516DE];;y/05/os/&print;
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