Re: testing defined($x) && length($x)

Why are you not just doing this?

if ($x and length($x)) {} # Do something
[download]

This should take care of your $x not being defined.

Update: Too early did not think clearly see below. Removed the offending/incorrect text.

Comment on Re: testing defined($x) && length($x) Download Code

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Re^2: testing defined($x) && length($x) by kennethk (Abbot) on Mar 25, 2009 at 16:34 UTC
No, it still has the '0' false negative: `$ perl -e '$x = 0; print "failed\n" unless $x and length($x)' failed $` [download] vs. `$ perl -e '$x=0; $ print "failed\n" unless defined $x and length($x)' $` [download]	[reply] [d/l] [select]
Re^2: testing defined($x) && length($x) by Bloodnok (Vicar) on Mar 25, 2009 at 16:41 UTC
...length test will catch it if the value of $x = 0, hmmm, if `$x == 0`, then `length()` test will not be executed - aka, it suffers from the same problem (with my attempt) that ikegami kindly pointed out. A user level that continues to overstate my experience :-))	[reply] [d/l] [select]