Re: Can't modify private array in division (/) at lib.pl line 31, near "2;"

You cannot divide arrays by 2, which is what you are doing in calcarr. Perhaps you want:

sub calcarr {map {$_ / 2} @_}
my @arr = calcarr(@funcArr);
[download]

Note the @arr instead of $arr. But I've no idea what @funcArr is supposed to be - your main script uses it, but never assigns to it. In fact, I don't think your main script even compiles.

Comment on Re: Can't modify private array in division (/) at lib.pl line 31, near "2;" Download Code

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Re^2: Can't modify private array in division (/) at lib.pl line 31, near "2;" by jettero (Monsignor) on Apr 09, 2009 at 00:11 UTC
You cannot divide arrays by 2 I understand what you meant, but to be really pedantic ... I think you can divide them by two, but you can't assign it back... `$x = @a/2` fine, `@x = 2` not so much... and that's what `@a /= 2` is doing, but it's doing it to a protected value, which is the size of the array. UPDATE: I understand that it's not what he wants and that your answer is essentially correct. I was correcting the very small pedantic point that you can divide an array by 2, you just can't set its size to 2 with @a/=2. I definitely wasn't clear on what I meant either though. @x=2 is fine, but it's really @x=(2). You can't actually express what @a/=2 is assigning, which is @a.size = @a/2. Looks like ruby or something -- you could express it with splice, but you'd have to (at least implicitly) mention the start and end of your size reduction. -Paul	[reply] [d/l] [select]
Re^3: Can't modify private array in division (/) at lib.pl line 31, near "2;" by JavaFan (Canon) on Apr 09, 2009 at 08:40 UTC
`@a / 2` gives you half the number of elements in `@a`. Which isn't even close to what the OP wants to achieve. You can BTW assign such a result back: `$ perl -wE '@a = "a" .. "z"; @a = @a / 2; say @a' 13` [download] But `@a /= 2` will fail. However, it has little to do what the OP wants.	[reply] [d/l] [select]
Re^2: Can't modify private array in division (/) at lib.pl line 31, near "2;" by Ciao (Initiate) on Apr 09, 2009 at 00:56 UTC
@funcArr is supposed to be the "NEW" array containing all the values of the old array divided by 2. Ciao	[reply]