Re^6: Challenge: prefix($x, $y) . suffix($x, $z) eq $x

shmem,
Much better - but it helped me find another bug in your code.

$perl shmem.pl hello
found: prefix(haughtiness humanoid ... hello
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prefix(hello, hello) ne 'h' for a number of reasons. First, they have more in common then h. Second, it would consume the entire word - both of which are against the rules.

Cheers - L~R

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Re^7: Challenge: prefix($x, $y) . suffix($x, $z) eq $x by shmem (Chancellor) on Apr 23, 2009 at 00:43 UTC
No, Sir. It is not prefix(hello, hello), but prefix(haughtiness, hello) etc. haughtiness, humanoid and hello have the prefix 'h' in common, and the 'ello' is provided by the words output in the suffix section. Run the `prefix()` sub passing it `(qw(hello hello))` and you will get no return value. So (~~humanoid~~ hello, haughtiness, cello) is a valid tuple. ~~The presence of 'hello' in the prefix section is an artifact of the implementation... er, bug~~ ;-) --shmem	[reply] [d/l] [select]
Re^8: Challenge: prefix($x, $y) . suffix($x, $z) eq $x by Limbic~Region (Chancellor) on Apr 23, 2009 at 00:51 UTC
shmem, Well, the title does say prefix($x, $y) . prefix($x, $z) eq $x. In this case, $x should be 'hello'. After your explanation and examining the code that I see you are listing all words that have the same prefix which is effectively the right thing - just not displayed as expected. Cheers - L~R	[reply]