Re: need both from system-call

Upps I discovered $?. But there is a strange behavior in the following codes:
xx.pl:


#!/usr/bin/perl

print"STATUS:$?\n";

$result=`./xxx.pl`;
$status=$?;

print "RES:$result\nSTA:$status\n";
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xxx.pl:

#!/usr/bin/perl

print"Wonderful world on Friday\n";
exit 200;
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This results in:

STATUS:0
RES:Wonderful world on Friday

STA:25600
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Why ???
Is 255 the return code from the second #!/usr/bin/perl ?
I'm a little bit confused ...


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Re: Re: need both from system-call by birdbrane (Chaplain) on Apr 27, 2001 at 16:20 UTC
Look under "exit status" of the camel book. $? is the entire 16 bit status code. You only want the last 8 bits. This will fix your code: `$status = $? >> 8;` bb	[reply] [d/l]
Re: Re: need both from system-call by hdp (Beadle) on Apr 27, 2001 at 16:20 UTC
As perlvar documents, `$?` is "just the 16-bit status word returned by the wait() system call (or else is made up to look like it). Thus, the exit value of the subprocess is really ('$? >> 8')". It looks like perl thinks the exit value it got was 100. hdp.	[reply] [d/l]