Re: Difficulties with split

my 2 cents...

#!/usr/bin/perl
use warnings;
$in = $ARGV[0];
@vals = split(/\.\./, $in);
print @vals;
[download]

perliff

----------------------

"with perl on my side"

Comment on Re: Difficulties with split Download Code

Replies are listed 'Best First'.
Re^2: Difficulties with split by johngg (Canon) on Apr 28, 2009 at 22:12 UTC
A full stop is a regular expression metacharacter meaning match any character (with caveats, see perlretut, perlre). However, a backslash escapes the special meaning of a metacharacter so that `\.` matches a literal full stop. That means you are spliting on two literal full stops, which is not quite what was wanted. `$ perl -le ' > $in = q{abcdefg}; > @vals = split m{\.\.}, $in; > print for @vals;' abcdefg $ perl -le ' > $in = q{abc..defg}; > @vals = split m{\.\.}, $in; > print for @vals;' abc defg $` [download] I hope this is of interest. Cheers, JohnGG	[reply] [d/l] [select]

Replies are listed 'Best First'.

Re^2: Difficulties with split
by johngg (Canon) on Apr 28, 2009 at 22:12 UTC

A full stop is a regular expression metacharacter meaning match any character (with caveats, see perlretut, perlre). However, a backslash escapes the special meaning of a metacharacter so that \. matches a literal full stop. That means you are spliting on two literal full stops, which is not quite what was wanted.

$ perl -le '
> $in = q{abcdefg};
> @vals = split m{\.\.}, $in;
> print for @vals;'
abcdefg
$ perl -le '
> $in = q{abc..defg};
> @vals = split m{\.\.}, $in;
> print for @vals;'
abc
defg
$
[download]

I hope this is of interest.

Cheers,

JohnGG

[reply]
[d/l]
[select]