Re: scope of my $x in if statements

I want the $x in g($x) to reference the lexical $x on the same line.

That's currently not possible in order to allow

my $x = $x;  # Initialize with value from outer scope.
[download]

The clearest alternative is probably

my $x = f();

if ($x and g($x)) {
   ...
}
[download]

if (my $x = f()) {
   if (g($x)) {
      ...
   }
}
[download]

Comment on Re: scope of my $x in if statements Select or Download Code

Replies are listed 'Best First'.
Re^2: scope of my $x in if statements by ig (Vicar) on May 08, 2009 at 01:32 UTC
The first expands the scope of $x.	[reply]
Re^3: scope of my $x in if statements by ikegami (Patriarch) on May 08, 2009 at 01:54 UTC
So?	[reply]
Re^4: scope of my $x in if statements by ig (Vicar) on May 08, 2009 at 02:05 UTC
Just a nit, unless one is concerned that this $x should be out of scope after the end of the if block. The outer scope could have its own $x, for example.	[reply]
Re^5: scope of my $x in if statements by ikegami (Patriarch) on May 08, 2009 at 03:32 UTC
Re^6: scope of my $x in if statements by ig (Vicar) on May 08, 2009 at 07:17 UTC