in reply to How do I use the output of one perls script as the input of another on the commandline? like a pipeline

I'm sure you have read perlrun. It says:

Upon startup, Perl looks for your program in one of the following places:
  1. Specified line by line via -e or -E switches on the command line.
  2. Contained in the file specified by the first filename on the command line. (Note that systems supporting the #! notation invoke interpreters this way. See "Location of Perl".)
  3. Passed in implicitly via standard input. This works only if there are no filename arguments--to pass arguments to a STDIN-read program you must explicitly specify a "-" for the program name.

Maybe you can help us improve the documentation and tell how to express this more clear?

  • Comment on Re: How do I use the output of one perls script as the input of another on the commandline? like a pipeline

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