in reply to Hash Within A Hash

Unfortunatly, I have no control over the call. What I have to do is build the original Hash from the call. I went and tried what Zero suggested and it still doesn't want to give the value up.

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Re^2: Hash Within A Hash
by CountZero (Bishop) on May 20, 2009 at 06:03 UTC
    What do you mean with I have no control over the call.?

    You are not "calling" anything in your code.

    CountZero

    A program should be light and agile, its subroutines connected like a string of pearls. The spirit and intent of the program should be retained throughout. There should be neither too little or too much, neither needless loops nor useless variables, neither lack of structure nor overwhelming rigidity." - The Tao of Programming, 4.1 - Geoffrey James